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  1. What is the square root of 2501 ? | Socratic

    Note that the prime factorisation of 2501 is: 2501 = 41 ⋅ 61 With no square factors, the square root cannot be simplified. Note that 502 = 2500 so √2501 will be an irrational number a little more …

  2. Question #b5f73 - Socratic

    Then, we can just find the mass of 2.272 carbon atoms by multiplying 2.272 by the mass of 1 mole of carbon: 2.272 xx 12.01 = "27.29g" Since there was 1 significant figure in the question, …

  3. Question #004f2 - Socratic

    0.56 1 molar solution ="Number of moles of solute"/"Volume of solution" for Sugar C_ (12)H_ (22)O_ (11) molar mass=342gm according to equation and information provided 1= …

  4. Question #0a3ea - Socratic

    So number of atoms in 0.5 mole of CH_4 is equal to number of molecules in 0.5 mol multiplied by 5. "number of atoms in 0.5 mole of CH_4"= "5⋅number of molecules in 0.5 mol" = …

  5. If #a^2 + b^2 = c^2# = 12.85 and ab=5.58, then (a + b)^2

    (a+b)^2=24.01 >"note that " (a+b)^2=a^2+2ab+b^2 color (white) (xxxxx)=a^2+b^2+2ab color (white) (xxxxx)=12.85+ (2xx5.58) color (white) (xxxxx)=12.85+11.16=24.01

  6. 1545 subjects were given ginko & 1524 placebo. In ginko

    Oct 11, 2015 · 1545 subjects were given ginko & 1524 placebo. In ginko group, 246 developed dementian & in the placebo it was 277 with dementia. Significance level=0.01 to test claim …

  7. How many molecules of N_2O_3 are present in 28.3 g of N_2O_3?

    2.228 × 10^"23" molecules. 1 mole contains 6.022140857 × 10^"23" (Avogadro's number) The molecular weight of N_2O_3 is: 76.01 g/mol You have 28.3 g, so you have 28.3 / 76.01 = 0.37 …

  8. A pendulum swinging in simple harmonic motion has an ... - Socratic

    The pendulum reaches a displacement of 10mm in 0.0314 s after crossing the equilibrium point. The frequency is 5 Hz and the amplitude is 0.012 m. One function that could result in the …

  9. Question #cbccf - Socratic

    The concentration of "Pb"^"2+" at equilibrium is 9.3 × 10^"-5"color (white) (l) "mol/L". > We can solve this by setting up an ICE table. color (white) (mmmmmm)"Pb (s ...

  10. Question #94c52 - Socratic

    Using the isotopic masses and their relative abundance, the average atomic mass comes out to 24.3051 u . You work this out as a weighted average. Each isotope's mass is multiplied by its …